How to Build a 12-volt DC LED Light
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How to Build a 12-volt DC LED Light
by Admin Thu Dec 18, 2014 7:46 am
How to Build a 12-volt DC LED Light
An LED is a diode optimized to emit light. LEDs have many useful applications, such as in electronics, security, transportation and toys.
Because they are semiconductors, LEDs are delicate and prone to breakage if too much current runs through them. To avoid this problem, use them in combination with a resistor. The resistor's value may be calculated with Ohm's Law. The 12 volts may be generated with the use of batteries or a DC power supply. Electronic circuit trainers also may produce the needed voltage.
Instructions
1
Study how to calculate the value for the resistor R. Using Ohm's Law, the general formula is R = (Voltage Source -- LED Voltage) / LED Current. Note that R is the minimal resistance that should be used. It may be necessary to use a larger size.
2
Calculate the minimum value of R for a current of 20 milliamps. It is R is (12 V -- 1.8 V) / 0.020 = 510 ohms. This is not a standard resistance value. Use 560 ohms.
3.Build a series circuit with the 12-volt source, 560-ohm resistor and LED. Using jumper wires, attach one end of the resistor to the positive terminal of the power supply. Wire the resistor's other end to the positive side of the LED. To recall, the positive side usually has a longer lead than the negative one at the bottom. However, the negative lead is normally longer at the top, inside the plastic casing.
4
Connect the negative side of the LED to the power supply's ground. Turn the power supply on. The LED will light. If the LED is not bright enough, redo the calculations to use a current of 25 milliamps, in which case the resistor value that should be used is 470 ohms.
Tips & Warnings
Never use a resistor value that is below that of the calculated minimum value.
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An LED is a diode optimized to emit light. LEDs have many useful applications, such as in electronics, security, transportation and toys.
Because they are semiconductors, LEDs are delicate and prone to breakage if too much current runs through them. To avoid this problem, use them in combination with a resistor. The resistor's value may be calculated with Ohm's Law. The 12 volts may be generated with the use of batteries or a DC power supply. Electronic circuit trainers also may produce the needed voltage.
Instructions
1
Study how to calculate the value for the resistor R. Using Ohm's Law, the general formula is R = (Voltage Source -- LED Voltage) / LED Current. Note that R is the minimal resistance that should be used. It may be necessary to use a larger size.
2
Calculate the minimum value of R for a current of 20 milliamps. It is R is (12 V -- 1.8 V) / 0.020 = 510 ohms. This is not a standard resistance value. Use 560 ohms.
3.Build a series circuit with the 12-volt source, 560-ohm resistor and LED. Using jumper wires, attach one end of the resistor to the positive terminal of the power supply. Wire the resistor's other end to the positive side of the LED. To recall, the positive side usually has a longer lead than the negative one at the bottom. However, the negative lead is normally longer at the top, inside the plastic casing.
4
Connect the negative side of the LED to the power supply's ground. Turn the power supply on. The LED will light. If the LED is not bright enough, redo the calculations to use a current of 25 milliamps, in which case the resistor value that should be used is 470 ohms.
Tips & Warnings
Never use a resistor value that is below that of the calculated minimum value.
Dreambox DM7080HD
dm7080HD
cheap dreambox DM8000HD
led wall washer light
led pixell light
LED Underwater LightLED Spot Light
LED Spot Light
dm8000
DM7080 HD
Dreambox DM8000 HD
DM8000 HD
DM8000
dreambox dm7020 HD 7020 HD
DM7020 HD
DM500 HD DM500 HD V2
Dreambox dm500 HD
DM800 HD SE v2
dreambox dm800 HD SE V2
Dreambox dm800 HD SE V2 DM800 HD SE
Dreambox DM800 HD SE DM800 HD SE
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wholesale lenovo cellphone
Lenovo K920
Lenovo K910 VIBE Z
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DM7020HD V2 DECODER DREAMBOX
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